通过OD载入,分析代码,得出解密脚本
- m="swfxc{gdv}fwfctslydRddoepsckaNDMSRITPNsmr1_=2cdsef66246087138"
- t="1,4,E,A,5,24,17,2A,D,13,1C,D,1B,27,30,29,2A,1A,14,3B,4"
- c=t.split(',')
- length=17
- i=0
- t=""
- while i<length:
- index=c[i]
- t=t+m[int(index,16)]
- i+=1
- print(t)
复制代码 得出解密后明文:wctf{Pe_cRackme1_
继续看代码,后面还有几个判断
前后拼接 wctf{Pe_cRackme1_1024}
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